If you use the above triangle, then you get the sequence b1=1,b2=1,b3=2+1=3,b4=2+2=4,b5=3+4+1=8,b6=3+6+3=12,b7=4+9+7+1=21,....
In this way we get the sequence {1, 1, 3, 4, 8, 12, 21, ...}.
Here we colored the numbers to show how numbers on diagonals add to a sequence.
 
The above sequence satisfies the following equation.
 
f(1)= 1, f(2)=1 and f(n)=f(n-1)+f(n-2)+
 
 
 
We can generalize this fact.
Let p be a natural number. Similarly by using {U(p,n,m,1), n = 1, 2, 3, ...,10 and m = 1, ...,n} we get the following sequence of Definition 1.
 
 
Definition 3.
 
  
 
 
 
When p = 4, the sequence of Definition 3 is {1,1,2,3,6,9,15,24,40,64,104,168,273,441,714,1155,1870,3025,4895,7920}.
 
There is a very simple relation between this sequence and the Fibonacci sequence F(n).
We omit the proof of theorems and lemmas here. If you want to read proofs, please click Proof.
 
Theorem 3. Suppose that f(n) is the sequence of Definition 3 for p = 4. Then
 
 
 
 
 
 
 
We omit the proof of this theorem, since this is a special case of Theorem 5.
 
From the above relation it is easy to get the following elegant relation.
 
Theorem 4. Under the same condition of Theorem 3 we have the following relations.
 
 
 
 
 
 
 
 
 
 
 
 
Remark. It took  more than 1 month for us to discover the above relations, and these relations are going to be published in Reference [8].
It is well known that F(n+1)/F(n) converges to the golden ratio when we make n bigger, and this is one of the reason why Fibonacci sequence is very useful in many field of science and technology.
By the above formula our sequence has the same property, and we are looking for new application of our sequences.
 
After we submitted these relations to the journal, we could generalize the formula and got the following theorem.
 
Theorem 5. Suppose that p=4q for some natural number q, then the sequence of Definition 1 satisfies the following relations. Here n is non negative integer.
 
 
 
 
 
 
 
 
 
 
 
It is well known that the numbers on diagonals of the Pascal's triangle add to the Fibonacci sequence,but the numbers on diagonals of our triangles add to Fibonacci like sequences.We are going to illustrate this fact.
By using {U(2,n,m,1), n = 1, 2, 3, ...,10 and m = 1, ...,n} we get the following triangle.
In the 12th century  Fibonacci discovered a very interesting sequence.
 
In the 21th century the authors discovered Fibonacci-like sequences that are very interesting.
 
 
The relation in Theorem 5 is quite simple, but it is valid only when p is a multiple of 4.
We looked for relations that are valid for arbitrary natural number p, and discovered two Theorems.
Theorem 6 is for even number, and Theorem 7 is for odd number.
 
 
Theorem 6.  Suppose that p is an even number, then the sequence of Definition 3 satisfies the following relations. Here n is non negative integer and we define F(0) = 0.
 
 
 
 
 
 
 
 
 
 
 
                                         ...(9).
Theorem 7.  Suppose that p is an odd number, then the sequence of Definition 1 satisfies the following relations. Here n is non negative integer and we define F(0) = 0.
 
 
 
 
 
 
 
 
 
 
 
                                   ...(13).
 
 
 
 
 
 
⇒Go to Section 5Gallery.htmlAbout_our_reserch.htmlshapeimage_3_link_0
⇒Back to the homeAbout_our_reserch.htmlAbout_our_reserch.htmlshapeimage_4_link_0